24x^2=160x

Solution for 24x^2=160x equation:

24x^2=160x

We move all terms to the left:

24x^2-(160x)=0

a = 24; b = -160; c = 0;
Δ = b2-4ac
Δ = -1602-4·24·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-160}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+160}{2*24}=\frac{320}{48}
=6+2/3
$